Optimal. Leaf size=111 \[ \frac {5 a^3 (A+B) \sin (c+d x)}{2 d}+\frac {(3 A+5 B) \sin (c+d x) \left (a^3 \cos (c+d x)+a^3\right )}{6 d}+\frac {1}{2} a^3 x (7 A+5 B)+\frac {a^3 A \tanh ^{-1}(\sin (c+d x))}{d}+\frac {a B \sin (c+d x) (a \cos (c+d x)+a)^2}{3 d} \]
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Rubi [A] time = 0.30, antiderivative size = 111, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.172, Rules used = {2976, 2968, 3023, 2735, 3770} \[ \frac {5 a^3 (A+B) \sin (c+d x)}{2 d}+\frac {(3 A+5 B) \sin (c+d x) \left (a^3 \cos (c+d x)+a^3\right )}{6 d}+\frac {1}{2} a^3 x (7 A+5 B)+\frac {a^3 A \tanh ^{-1}(\sin (c+d x))}{d}+\frac {a B \sin (c+d x) (a \cos (c+d x)+a)^2}{3 d} \]
Antiderivative was successfully verified.
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Rule 2735
Rule 2968
Rule 2976
Rule 3023
Rule 3770
Rubi steps
\begin {align*} \int (a+a \cos (c+d x))^3 (A+B \cos (c+d x)) \sec (c+d x) \, dx &=\frac {a B (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d}+\frac {1}{3} \int (a+a \cos (c+d x))^2 (3 a A+a (3 A+5 B) \cos (c+d x)) \sec (c+d x) \, dx\\ &=\frac {a B (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d}+\frac {(3 A+5 B) \left (a^3+a^3 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\frac {1}{6} \int (a+a \cos (c+d x)) \left (6 a^2 A+15 a^2 (A+B) \cos (c+d x)\right ) \sec (c+d x) \, dx\\ &=\frac {a B (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d}+\frac {(3 A+5 B) \left (a^3+a^3 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\frac {1}{6} \int \left (6 a^3 A+\left (6 a^3 A+15 a^3 (A+B)\right ) \cos (c+d x)+15 a^3 (A+B) \cos ^2(c+d x)\right ) \sec (c+d x) \, dx\\ &=\frac {5 a^3 (A+B) \sin (c+d x)}{2 d}+\frac {a B (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d}+\frac {(3 A+5 B) \left (a^3+a^3 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\frac {1}{6} \int \left (6 a^3 A+3 a^3 (7 A+5 B) \cos (c+d x)\right ) \sec (c+d x) \, dx\\ &=\frac {1}{2} a^3 (7 A+5 B) x+\frac {5 a^3 (A+B) \sin (c+d x)}{2 d}+\frac {a B (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d}+\frac {(3 A+5 B) \left (a^3+a^3 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\left (a^3 A\right ) \int \sec (c+d x) \, dx\\ &=\frac {1}{2} a^3 (7 A+5 B) x+\frac {a^3 A \tanh ^{-1}(\sin (c+d x))}{d}+\frac {5 a^3 (A+B) \sin (c+d x)}{2 d}+\frac {a B (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d}+\frac {(3 A+5 B) \left (a^3+a^3 \cos (c+d x)\right ) \sin (c+d x)}{6 d}\\ \end {align*}
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Mathematica [A] time = 0.28, size = 113, normalized size = 1.02 \[ \frac {a^3 \left (9 (4 A+5 B) \sin (c+d x)+3 (A+3 B) \sin (2 (c+d x))-12 A \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )+12 A \log \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )+42 A d x+B \sin (3 (c+d x))+30 B d x\right )}{12 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.81, size = 102, normalized size = 0.92 \[ \frac {3 \, {\left (7 \, A + 5 \, B\right )} a^{3} d x + 3 \, A a^{3} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, A a^{3} \log \left (-\sin \left (d x + c\right ) + 1\right ) + {\left (2 \, B a^{3} \cos \left (d x + c\right )^{2} + 3 \, {\left (A + 3 \, B\right )} a^{3} \cos \left (d x + c\right ) + 2 \, {\left (9 \, A + 11 \, B\right )} a^{3}\right )} \sin \left (d x + c\right )}{6 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.45, size = 180, normalized size = 1.62 \[ \frac {6 \, A a^{3} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 6 \, A a^{3} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) + 3 \, {\left (7 \, A a^{3} + 5 \, B a^{3}\right )} {\left (d x + c\right )} + \frac {2 \, {\left (15 \, A a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 15 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 36 \, A a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 40 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 21 \, A a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 33 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{3}}}{6 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.14, size = 153, normalized size = 1.38 \[ \frac {A \,a^{3} \cos \left (d x +c \right ) \sin \left (d x +c \right )}{2 d}+\frac {7 A \,a^{3} x}{2}+\frac {7 A \,a^{3} c}{2 d}+\frac {B \sin \left (d x +c \right ) \left (\cos ^{2}\left (d x +c \right )\right ) a^{3}}{3 d}+\frac {11 a^{3} B \sin \left (d x +c \right )}{3 d}+\frac {3 a^{3} A \sin \left (d x +c \right )}{d}+\frac {3 a^{3} B \cos \left (d x +c \right ) \sin \left (d x +c \right )}{2 d}+\frac {5 a^{3} B x}{2}+\frac {5 a^{3} B c}{2 d}+\frac {A \,a^{3} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.52, size = 141, normalized size = 1.27 \[ \frac {3 \, {\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} A a^{3} + 36 \, {\left (d x + c\right )} A a^{3} - 4 \, {\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} B a^{3} + 9 \, {\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} B a^{3} + 12 \, {\left (d x + c\right )} B a^{3} + 12 \, A a^{3} \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + 36 \, A a^{3} \sin \left (d x + c\right ) + 36 \, B a^{3} \sin \left (d x + c\right )}{12 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.42, size = 178, normalized size = 1.60 \[ \frac {3\,A\,a^3\,\sin \left (c+d\,x\right )}{d}+\frac {15\,B\,a^3\,\sin \left (c+d\,x\right )}{4\,d}+\frac {7\,A\,a^3\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )}{d}+\frac {2\,A\,a^3\,\mathrm {atanh}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )}{d}+\frac {5\,B\,a^3\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )}{d}+\frac {A\,a^3\,\sin \left (2\,c+2\,d\,x\right )}{4\,d}+\frac {3\,B\,a^3\,\sin \left (2\,c+2\,d\,x\right )}{4\,d}+\frac {B\,a^3\,\sin \left (3\,c+3\,d\,x\right )}{12\,d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ a^{3} \left (\int A \sec {\left (c + d x \right )}\, dx + \int 3 A \cos {\left (c + d x \right )} \sec {\left (c + d x \right )}\, dx + \int 3 A \cos ^{2}{\left (c + d x \right )} \sec {\left (c + d x \right )}\, dx + \int A \cos ^{3}{\left (c + d x \right )} \sec {\left (c + d x \right )}\, dx + \int B \cos {\left (c + d x \right )} \sec {\left (c + d x \right )}\, dx + \int 3 B \cos ^{2}{\left (c + d x \right )} \sec {\left (c + d x \right )}\, dx + \int 3 B \cos ^{3}{\left (c + d x \right )} \sec {\left (c + d x \right )}\, dx + \int B \cos ^{4}{\left (c + d x \right )} \sec {\left (c + d x \right )}\, dx\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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